-325=p^2+p-60p

Solution for -325=p^2+p-60p equation:

-325=p^2+p-60p

We move all terms to the left:

-325-(p^2+p-60p)=0

We get rid of parentheses

-p^2-p+60p-325=0

We add all the numbers together, and all the variables

-1p^2+59p-325=0

a = -1; b = 59; c = -325;
Δ = b2-4ac
Δ = 592-4·(-1)·(-325)
Δ = 2181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{2181}}{2*-1}=\frac{-59-\sqrt{2181}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{2181}}{2*-1}=\frac{-59+\sqrt{2181}}{-2}
$